Can I perform HTTP POST requests with urllib3, and if so, how?

Yes, you can perform HTTP POST requests using urllib3. urllib3 is a powerful, user-friendly HTTP client for Python that provides many features, such as connection pooling and thread safety.

Here's how you can perform an HTTP POST request using urllib3:

First, you'll need to install urllib3 if you haven't already. You can install it using pip:

pip install urllib3

Then, you can use the following code to perform a POST request:

import urllib3
import json

# Create a PoolManager instance for sending requests.
http = urllib3.PoolManager()

# Define the URL you want to send a POST request to.
url = ''

# Define the data you want to send in the POST request.
# This can either be form-encoded data or JSON.
data = {
    'key1': 'value1',
    'key2': 'value2'

# Convert the dictionary to URL-encoded string.
encoded_data = json.dumps(data).encode('utf-8')

# Set headers, if necessary. JSON content-type is set in this example.
headers = {
    'Content-Type': 'application/json'

# Send a POST request with the specified data and headers.
response = http.request(

# Print the response status code and data.
print(f'Status Code: {response.status}')
print(f'Response Body: {"utf-8")}')

In this example, we've done the following:

  1. Created a PoolManager which handles all of our HTTP requests and connection pooling.
  2. Defined the URL to which we want to send a POST request.
  3. Created a dictionary with the data we want to send.
  4. Converted the dictionary to a JSON string and then encoded it to bytes, which is necessary for sending in the HTTP request body.
  5. Set the appropriate headers. If you're sending JSON data, you should set the Content-Type header to application/json.
  6. Sent the POST request with the http.request() method, specifying the method 'POST', along with the URL, data, and headers.
  7. Printed out the response status code and body.

Note that urllib3 does not handle JSON serialization or deserialization on its own, so you have to manually serialize your data to a JSON string using json.dumps() if you're sending JSON data. Similarly, if you receive JSON data in the response, you'll need to deserialize it using json.loads().

Remember that urllib3 can throw exceptions, so in a production environment, you should wrap your request in a try-except block to handle possible exceptions like urllib3.exceptions.HTTPError.

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